Among NO_3^{-} (I),AsO_3^{3-} (II),CO_3^{2-} | vedclass

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(A) To determine the geometry,we calculate the hybridization of the central atom using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the

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$II, IV, V$

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(A) To determine the geometry,we calculate the hybridization of the central atom using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence electrons,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.SpeciesHybridizationGeometry$NO_3^{-}$$sp^2$Trigonal planar (Planar)$AsO_3^{3-}$$sp^3$Pyramidal (Non-planar)$CO_3^{2-}$$sp^2$Trigonal planar (Planar)$ClO_3^{-}$$sp^3$Pyramidal (Non-planar)$SO_3^{2-}$$sp^3$Pyramidal (Non-planar)Thus,the non-planar species are $AsO_3^{3-} (II)$,$ClO_3^{-} (IV)$,and $SO_3^{2-} (V)$.

List-$I$	List-$II$
$A. XeF_4$	$I. See-saw$
$B. SF_4$	$II. Square planar$
$C. NH_4^{+}$	$III. Bent T-shaped$
$D. BrF_3$	$IV. Tetrahedral$

Among $NO_3^{-} (I)$,$AsO_3^{3-} (II)$,$CO_3^{2-} (III)$,$ClO_3^{-} (IV)$,and $SO_3^{2-} (V)$,the non-planar species are:

Similar Questions

Statement $I$ : $SO_2$ and $H_2O$ both possess $V$-shaped structure.
Statement $II$ : The bond angle of $SO_2$ is less than that of $H_2O$.
In the light of the above statements,choose the most appropriate answer from the options given below:

Which of the following compounds is octahedral?

Identify the correct statement about $\text{ClF}_3$ from the following options :

Match List-$I$ with List-$II$:
List-$I$ List-$II$
$A. XeF_4$ $I. See-saw$
$B. SF_4$ $II. Square planar$
$C. NH_4^{+}$ $III. Bent T-shaped$
$D. BrF_3$ $IV. Tetrahedral$

Choose the correct answer from the options given below:

Which species has the same shape as $NH_3$?

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